Objective: To study vector addition by:
- Graphical means
- Using components.
A circular force table is used to check results.
Materials:
- Circular force table
- Masses
- Mass holders
- String
- Protractor
- Four pulleys.
Circular Force Table, Pulleys, Masses, Mass Holders, and String |
Procedure:
- Your instructor will give each group three masses in grams (which will represent the magnitude of three forces) and three angles. Choose a scale of 1 cm = 20 grams, make a vector diagram (figure 3) showing these forces, and graphically find their resultant. Determine the magnitude (length) and direction (angle) of the resultant force using a ruler and protractor (figure 4).
- Make a second vector diagram and show the same three forces again and find the resultant vector by components (figure 5). Show the components of each vector as well as the resultant vector on your diagram. Draw the force (vector) you would need to exactly cancel out this resultant.
- Mount three pulleys on the edge of your force table at the angles given above. Attach strings to the center ring so that they each run over the pulley and attach to a mass holder as shown in the figure below. Hang the appropriate masses (numerically equal to the forces in grams) on each string. Set up a fourth pulley and mass holder at 180 degrees opposite from the angle you calculated for the resultant of the first three vectors. Record all mass and angles. If properly done, the ring in the center of the circular force table should be in equilibrium. Ask your instructor to check your results before going on.
- Confirm your results by simulation at the website:http://phet.colorado.edu/en/simulation/vector-addition. Add the vectors and obtain a resultant. Draw a diagram showing how you verified the result.
- In your conclusions, summarize what you learned and discuss any sources of error.
Results:
Figure 1 |
Figure 4
Adding Vectors by
Ruler and Protractor
|
Figure 5 Adding Vectors by Components |
Figure 6 |
Figure 7 |
Given the masses that represent the magnitude of vectors (100, 200, and 160) and the angles (0, 71, and 144) of inclination for those vectors respectively, figure 3 illustrates the resultant vector and the negative of the resultant vector. These vectors are necessary because they allow us to counter-balance the force table's mass vectors and place the vectors in equilibrium as seen in figure 1.
To calculate the magnitude and angle of the resultant vector:
R_x = (100cos0) + (200cos71) + (160cos144) = 36.1
R_y = (100sin0) + (200sin71) + (160sin144) = 283
θ = 82.7
R = (283^2 + 36.1^2)^(1/2) = 285.3
According to the data we collected and the vectors calculated, the approximation of the vectors we visualized online (figures 6 and 7) were close to our exact answers.
Conclusion:
During our experiment we learned that in order to place three forces in equilibrium a fourth force was necessary to counter-balance the other three. The counter-balancing force was exactly equal to the negative of the resultant of the sum of the first three forces (calculated as vectors).
Any source of error that was present was a result of human miscalculation.
R = (283^2 + 36.1^2)^(1/2) = 285.3
According to the data we collected and the vectors calculated, the approximation of the vectors we visualized online (figures 6 and 7) were close to our exact answers.
Conclusion:
During our experiment we learned that in order to place three forces in equilibrium a fourth force was necessary to counter-balance the other three. The counter-balancing force was exactly equal to the negative of the resultant of the sum of the first three forces (calculated as vectors).
Any source of error that was present was a result of human miscalculation.